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8n^2+n-636=0
a = 8; b = 1; c = -636;
Δ = b2-4ac
Δ = 12-4·8·(-636)
Δ = 20353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{20353}}{2*8}=\frac{-1-\sqrt{20353}}{16} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{20353}}{2*8}=\frac{-1+\sqrt{20353}}{16} $
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